5y^2(y^2+4)=28-11y^2

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Solution for 5y^2(y^2+4)=28-11y^2 equation: 



5y^2(y^2+4)=28-11y^2

We move all terms to the left:

5y^2(y^2+4)-(28-11y^2)=0

We get rid of parentheses

5y^2(y^2+4)+11y^2-28=0

We add all the numbers together, and all the variables

11y^2+5y^2(y^2+4)-28=0

We move all terms containing y to the left, all other terms to the right

11y^2+5y^2(y^2+4)=28

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